BBS FOR BEAM

BAR BENDING SCHEDULE OF THE BEAM

In this bar bending schedule we find the different terms of terminology like shape of the bar, length of the bar, total length of the bar, number of bars in the beam and weight of the steel in the beam. The fallowing figure shows shape of the beam and cross section of the beam.

Dimensions:

Length of the beam =10m

Width of the beam = 400mm

Depth of the beam = 500mm

The above figure describes that the beam is supporting with two columns at the ends having with length 10m. In this beam 4nos bottom bars and 2nos top bars is provided with 500mm centre to centre stirrups. 

At the section A-A clearly shows cross section of the beam with depth and width 500mm and 400mm respectfully.

At the ends of the beam 0.2m width of the column is supported is also sown in the figure there for this are the known dimensions of above figure. 

There for now we are going to find out the bare bending schedule:

First one is bottom bars:

Length of the bottom bar:

L= length of the beam + two columns width – two sides clear cover + length of the hook bar at two sides   

                                                                        

                                               =10+0.2+0.2-(2×0.4)+12×d

                                    Whare 12d is hook length

                                       =10+0.2+0.2-(2×0.4)+12×2×0.012

(where d dia of the bar 12mm)

                                       =10.608m

There for total no of bars = 4

Total length of the bar    = 4×10.608m

Similarly top bar :

L= length of the beam + two columns width – two sides clear + cover length of the hook bar at two sides   

                                                                        

                                                  =10+0.2+0.2-(2×0.4)+12×d

                                                   =10+0.2+0.2-(2×0.4)+12×2×0.012

                                                   =10.608m

           There for no of top bars  =2

Total length of bar = 2×10.608

                                                 =21.216m

Stirrups :

Length = 2×(depth of the beam-clear cover)+2(width  of the beam-clear    cover)+2×(hook length)

          =2×(500-40)+2×(400-40)+2×(12d)

Where d is dia of the stirrup = 8mm

          =2×(500-40)+2×(400-40)+2×(12×8)

          =1662mm

          =1.622m

No of stirrups:    

 

                   = 20

Total length of the stirrup = 20×1.622

                               =33m

   

S.NO	Description	No of bars	Length (M)	Total length (M)
1	BOTTOM BAR	4	10.608	53.5
2	TOP BAR	2	10.608	21.216
3	STIRRUP	20	1.662	33

TOTAL LENGHT OF 12mm DIA BAR= 53.5+21.216

                   =74.716M

TOTAL WEIGHT d²

                   = 12²

                

   =66.40kg